thermodynamics problems and solutions
9 kJ/kg Since water is saturated, the specific internal energy is approximately: \[ u_{sat} = u_f + x(u_g - u_f) \] For saturated liquid, \( x=0 \): \[ u_{liquid} \approx 908.3 \text{ kJ/kg} \] Answer: \[ \boxed{ u \approx 908.3 \text{ kJ/kg} } \] Note: For saturated liquid